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(x+2)2=(x-5)2+7
We move all terms to the left:
(x+2)2-((x-5)2+7)=0
We multiply parentheses
2x-((x-5)2+7)+4=0
We calculate terms in parentheses: -((x-5)2+7), so:We get rid of parentheses
(x-5)2+7
We multiply parentheses
2x-10+7
We add all the numbers together, and all the variables
2x-3
Back to the equation:
-(2x-3)
2x-2x+3+4=0
We add all the numbers together, and all the variables
7!=0
There is no solution for this equation
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