(x+2)2=x2+12

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Solution for (x+2)2=x2+12 equation: 



(x+2)2=x2+12

We move all terms to the left:

(x+2)2-(x2+12)=0

We add all the numbers together, and all the variables

-(+x^2+12)+(x+2)2=0

We multiply parentheses

-(+x^2+12)+2x+4=0

We get rid of parentheses

-x^2+2x-12+4=0

We add all the numbers together, and all the variables

-1x^2+2x-8=0

a = -1; b = 2; c = -8;
Δ = b2-4ac
Δ = 22-4·(-1)·(-8)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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