(x+2)=(2x+4x-3)

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Solution for (x+2)=(2x+4x-3) equation:



(x+2)=(2x+4x-3)
We move all terms to the left:
(x+2)-((2x+4x-3))=0
We add all the numbers together, and all the variables
(x+2)-((6x-3))=0
We get rid of parentheses
x-((6x-3))+2=0
We calculate terms in parentheses: -((6x-3)), so:
(6x-3)
We get rid of parentheses
6x-3
Back to the equation:
-(6x-3)
We get rid of parentheses
x-6x+3+2=0
We add all the numbers together, and all the variables
-5x+5=0
We move all terms containing x to the left, all other terms to the right
-5x=-5
x=-5/-5
x=1

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