(x+20)(5x+1)=(x+5)(5x+36)

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Solution for (x+20)(5x+1)=(x+5)(5x+36) equation: 



(x+20)(5x+1)=(x+5)(5x+36)

We move all terms to the left:

(x+20)(5x+1)-((x+5)(5x+36))=0

We multiply parentheses ..

(+5x^2+x+100x+20)-((x+5)(5x+36))=0



We calculate terms in parentheses: -((x+5)(5x+36)), so:

(x+5)(5x+36)

We multiply parentheses ..

(+5x^2+36x+25x+180)

We get rid of parentheses

5x^2+36x+25x+180

We add all the numbers together, and all the variables

5x^2+61x+180

Back to the equation:

-(5x^2+61x+180)



We get rid of parentheses

5x^2-5x^2+x+100x-61x+20-180=0

We add all the numbers together, and all the variables

40x-160=0

We move all terms containing x to the left, all other terms to the right

40x=160

x=160/40

x=4

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