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(x+20)(x-18)=0
We multiply parentheses ..
(+x^2-18x+20x-360)=0
We get rid of parentheses
x^2-18x+20x-360=0
We add all the numbers together, and all the variables
x^2+2x-360=0
a = 1; b = 2; c = -360;
Δ = b2-4ac
Δ = 22-4·1·(-360)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-38}{2*1}=\frac{-40}{2} =-20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+38}{2*1}=\frac{36}{2} =18 $
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