(x+20)(x-3)(x+1)(x+6)=-96

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Solution for (x+20)(x-3)(x+1)(x+6)=-96 equation: 



(x+20)(x-3)(x+1)(x+6)=-96

We move all terms to the left:

(x+20)(x-3)(x+1)(x+6)-(-96)=0

We add all the numbers together, and all the variables

(x+20)(x-3)(x+1)(x+6)+96=0

We multiply parentheses ..

(+x^2-3x+20x-60)(x+1)(x+6)+96=0

We multiply parentheses ..

(+x^2-3x+20x-60)(+x^2+6x+x+6)+96=0

We move all terms containing x to the left, all other terms to the right

(+x^2-3x+20x-60)(+x^2+6x+x+6)=-96

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