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(x+20)(x-4)=476
We move all terms to the left:
(x+20)(x-4)-(476)=0
We multiply parentheses ..
(+x^2-4x+20x-80)-476=0
We get rid of parentheses
x^2-4x+20x-80-476=0
We add all the numbers together, and all the variables
x^2+16x-556=0
a = 1; b = 16; c = -556;
Δ = b2-4ac
Δ = 162-4·1·(-556)
Δ = 2480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2480}=\sqrt{16*155}=\sqrt{16}*\sqrt{155}=4\sqrt{155}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4\sqrt{155}}{2*1}=\frac{-16-4\sqrt{155}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4\sqrt{155}}{2*1}=\frac{-16+4\sqrt{155}}{2} $
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