(x+20)3x=44

Solution for (x+20)3x=44 equation:

(x+20)3x=44

We move all terms to the left:

(x+20)3x-(44)=0

We multiply parentheses

3x^2+60x-44=0

a = 3; b = 60; c = -44;
Δ = b2-4ac
Δ = 602-4·3·(-44)
Δ = 4128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4128}=\sqrt{16*258}=\sqrt{16}*\sqrt{258}=4\sqrt{258}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{258}}{2*3}=\frac{-60-4\sqrt{258}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{258}}{2*3}=\frac{-60+4\sqrt{258}}{6}
$