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(x+20)7x=360
We move all terms to the left:
(x+20)7x-(360)=0
We multiply parentheses
7x^2+140x-360=0
a = 7; b = 140; c = -360;
Δ = b2-4ac
Δ = 1402-4·7·(-360)
Δ = 29680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{29680}=\sqrt{16*1855}=\sqrt{16}*\sqrt{1855}=4\sqrt{1855}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-4\sqrt{1855}}{2*7}=\frac{-140-4\sqrt{1855}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+4\sqrt{1855}}{2*7}=\frac{-140+4\sqrt{1855}}{14} $
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