(x+25)+(2x+18)=(x2+3)

Solution for (x+25)+(2x+18)=(x2+3) equation:

(x+25)+(2x+18)=(x2+3)

We move all terms to the left:

(x+25)+(2x+18)-((x2+3))=0

We add all the numbers together, and all the variables

-((+x^2+3))+(x+25)+(2x+18)=0

We get rid of parentheses

-((+x^2+3))+x+2x+25+18=0


We calculate terms in parentheses: -((+x^2+3)), so:

(+x^2+3)

We get rid of parentheses

x^2+3

Back to the equation:

-(x^2+3)


We add all the numbers together, and all the variables

3x-(x^2+3)+43=0

We get rid of parentheses

-x^2+3x-3+43=0

We add all the numbers together, and all the variables

-1x^2+3x+40=0

a = -1; b = 3; c = +40;
Δ = b2-4ac
Δ = 32-4·(-1)·40
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-13}{2*-1}=\frac{-16}{-2}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+13}{2*-1}=\frac{10}{-2}
=-5
$