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(x+25)=2x(x+10)=
We move all terms to the left:
(x+25)-(2x(x+10))=0
We get rid of parentheses
x-(2x(x+10))+25=0
We calculate terms in parentheses: -(2x(x+10)), so:We get rid of parentheses
2x(x+10)
We multiply parentheses
2x^2+20x
Back to the equation:
-(2x^2+20x)
-2x^2+x-20x+25=0
We add all the numbers together, and all the variables
-2x^2-19x+25=0
a = -2; b = -19; c = +25;
Δ = b2-4ac
Δ = -192-4·(-2)·25
Δ = 561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{561}}{2*-2}=\frac{19-\sqrt{561}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{561}}{2*-2}=\frac{19+\sqrt{561}}{-4} $
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