(x+3)(2x+4)=12

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Solution for (x+3)(2x+4)=12 equation:


Simplifying
(x + 3)(2x + 4) = 12

Reorder the terms:
(3 + x)(2x + 4) = 12

Reorder the terms:
(3 + x)(4 + 2x) = 12

Multiply (3 + x) * (4 + 2x)
(3(4 + 2x) + x(4 + 2x)) = 12
((4 * 3 + 2x * 3) + x(4 + 2x)) = 12
((12 + 6x) + x(4 + 2x)) = 12
(12 + 6x + (4 * x + 2x * x)) = 12
(12 + 6x + (4x + 2x2)) = 12

Combine like terms: 6x + 4x = 10x
(12 + 10x + 2x2) = 12

Add '-12' to each side of the equation.
12 + 10x + -12 + 2x2 = 12 + -12

Reorder the terms:
12 + -12 + 10x + 2x2 = 12 + -12

Combine like terms: 12 + -12 = 0
0 + 10x + 2x2 = 12 + -12
10x + 2x2 = 12 + -12

Combine like terms: 12 + -12 = 0
10x + 2x2 = 0

Solving
10x + 2x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2x'.
2x(5 + x) = 0

Ignore the factor 2.

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0

Subproblem 2

Set the factor '(5 + x)' equal to zero and attempt to solve: Simplifying 5 + x = 0 Solving 5 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + x = 0 + -5 x = 0 + -5 Combine like terms: 0 + -5 = -5 x = -5 Simplifying x = -5

Solution

x = {0, -5}

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