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(x+3)(2x+4)=84
We move all terms to the left:
(x+3)(2x+4)-(84)=0
We multiply parentheses ..
(+2x^2+4x+6x+12)-84=0
We get rid of parentheses
2x^2+4x+6x+12-84=0
We add all the numbers together, and all the variables
2x^2+10x-72=0
a = 2; b = 10; c = -72;
Δ = b2-4ac
Δ = 102-4·2·(-72)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-26}{2*2}=\frac{-36}{4} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+26}{2*2}=\frac{16}{4} =4 $
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