(x+3)(2x-5)/x-2=0

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Solution for (x+3)(2x-5)/x-2=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

((x+3)*(2*x-5))/x-2 = 0

((x+3)*(2*x-5))/x+(-2*x)/x = 0

(x+3)*(2*x-5)-2*x = 0

2*x^2-x-15 = 0

2*x^2-x-15 = 0

2*x^2-x-15 = 0

DELTA = (-1)^2-(-15*2*4)

DELTA = 121

DELTA > 0

x = (121^(1/2)+1)/(2*2) or x = (1-121^(1/2))/(2*2)

x = 3 or x = -5/2

(x+5/2)*(x-3) = 0

((x+5/2)*(x-3))/x = 0

((x+5/2)*(x-3))/x = 0 // * x

(x+5/2)*(x-3) = 0

( x+5/2 )

x+5/2 = 0 // - 5/2

x = -5/2

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -5/2, 3 }

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