(x+3)(2x-7)+3=(2x+2)(x-4)

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Solution for (x+3)(2x-7)+3=(2x+2)(x-4) equation: 



(x+3)(2x-7)+3=(2x+2)(x-4)

We move all terms to the left:

(x+3)(2x-7)+3-((2x+2)(x-4))=0

We multiply parentheses ..

(+2x^2-7x+6x-21)-((2x+2)(x-4))+3=0



We calculate terms in parentheses: -((2x+2)(x-4)), so:

(2x+2)(x-4)

We multiply parentheses ..

(+2x^2-8x+2x-8)

We get rid of parentheses

2x^2-8x+2x-8

We add all the numbers together, and all the variables

2x^2-6x-8

Back to the equation:

-(2x^2-6x-8)



We get rid of parentheses

2x^2-2x^2-7x+6x+6x-21+8+3=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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