(x+3)(2x-7)+8=(x-4)(2x+2)

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Solution for (x+3)(2x-7)+8=(x-4)(2x+2) equation: 



(x+3)(2x-7)+8=(x-4)(2x+2)

We move all terms to the left:

(x+3)(2x-7)+8-((x-4)(2x+2))=0

We multiply parentheses ..

(+2x^2-7x+6x-21)-((x-4)(2x+2))+8=0



We calculate terms in parentheses: -((x-4)(2x+2)), so:

(x-4)(2x+2)

We multiply parentheses ..

(+2x^2+2x-8x-8)

We get rid of parentheses

2x^2+2x-8x-8

We add all the numbers together, and all the variables

2x^2-6x-8

Back to the equation:

-(2x^2-6x-8)



We get rid of parentheses

2x^2-2x^2-7x+6x+6x-21+8+8=0

We add all the numbers together, and all the variables

5x-5=0

We move all terms containing x to the left, all other terms to the right

5x=5

x=5/5

x=1

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