(x+3)(4x+5)=4x(x-4)-5

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Solution for (x+3)(4x+5)=4x(x-4)-5 equation: 



(x+3)(4x+5)=4x(x-4)-5

We move all terms to the left:

(x+3)(4x+5)-(4x(x-4)-5)=0

We multiply parentheses ..

(+4x^2+5x+12x+15)-(4x(x-4)-5)=0



We calculate terms in parentheses: -(4x(x-4)-5), so:

4x(x-4)-5

We multiply parentheses

4x^2-16x-5

Back to the equation:

-(4x^2-16x-5)



We get rid of parentheses

4x^2-4x^2+5x+12x+16x+15+5=0

We add all the numbers together, and all the variables

33x+20=0

We move all terms containing x to the left, all other terms to the right

33x=-20

x=-20/33

x=-20/33

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