(x+3)(4x-1)-(2x+1)(2x-1)=11x-2

Solution for (x+3)(4x-1)-(2x+1)(2x-1)=11x-2 equation:

(x+3)(4x-1)-(2x+1)(2x-1)=11x-2

We move all terms to the left:

(x+3)(4x-1)-(2x+1)(2x-1)-(11x-2)=0

We use the square of the difference formula

4x^2+(x+3)(4x-1)-(11x-2)+1=0

We get rid of parentheses

4x^2+(x+3)(4x-1)-11x+2+1=0

We multiply parentheses ..

4x^2+(+4x^2-1x+12x-3)-11x+2+1=0

We add all the numbers together, and all the variables

4x^2+(+4x^2-1x+12x-3)-11x+3=0

We get rid of parentheses

4x^2+4x^2-1x+12x-11x-3+3=0

We add all the numbers together, and all the variables

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$