(x+3)(x+2)=(x-6)(x-3)

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Solution for (x+3)(x+2)=(x-6)(x-3) equation: 



(x+3)(x+2)=(x-6)(x-3)

We move all terms to the left:

(x+3)(x+2)-((x-6)(x-3))=0

We multiply parentheses ..

(+x^2+2x+3x+6)-((x-6)(x-3))=0



We calculate terms in parentheses: -((x-6)(x-3)), so:

(x-6)(x-3)

We multiply parentheses ..

(+x^2-3x-6x+18)

We get rid of parentheses

x^2-3x-6x+18

We add all the numbers together, and all the variables

x^2-9x+18

Back to the equation:

-(x^2-9x+18)



We get rid of parentheses

x^2-x^2+2x+3x+9x+6-18=0

We add all the numbers together, and all the variables

14x-12=0

We move all terms containing x to the left, all other terms to the right

14x=12

x=12/14

x=6/7

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