(x+3)(x+2)=50

Solution for (x+3)(x+2)=50 equation:

(x+3)(x+2)=50

We move all terms to the left:

(x+3)(x+2)-(50)=0

We multiply parentheses ..

(+x^2+2x+3x+6)-50=0

We get rid of parentheses

x^2+2x+3x+6-50=0

We add all the numbers together, and all the variables

x^2+5x-44=0

a = 1; b = 5; c = -44;
Δ = b2-4ac
Δ = 52-4·1·(-44)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{201}}{2*1}=\frac{-5-\sqrt{201}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{201}}{2*1}=\frac{-5+\sqrt{201}}{2}
$