(x+3)(x+2)=x(x+4)-2

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Solution for (x+3)(x+2)=x(x+4)-2 equation:



(x+3)(x+2)=x(x+4)-2
We move all terms to the left:
(x+3)(x+2)-(x(x+4)-2)=0
We multiply parentheses ..
(+x^2+2x+3x+6)-(x(x+4)-2)=0
We calculate terms in parentheses: -(x(x+4)-2), so:
x(x+4)-2
We multiply parentheses
x^2+4x-2
Back to the equation:
-(x^2+4x-2)
We get rid of parentheses
x^2-x^2+2x+3x-4x+6+2=0
We add all the numbers together, and all the variables
x+8=0
We move all terms containing x to the left, all other terms to the right
x=-8

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