(x+3)(x+3)(x+3)-2=x(x+5)(x+4)-4

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Solution for (x+3)(x+3)(x+3)-2=x(x+5)(x+4)-4 equation: 



(x+3)(x+3)(x+3)-2=x(x+5)(x+4)-4

We move all terms to the left:

(x+3)(x+3)(x+3)-2-(x(x+5)(x+4)-4)=0

We multiply parentheses ..

(+x^2+3x+3x+9)(x+3)-(x(x+5)(x+4)-4)-2=0



We calculate terms in parentheses: -(x(x+5)(x+4)-4), so:

x(x+5)(x+4)-4

We multiply parentheses ..

x(+x^2+4x+5x+20)-4

We multiply parentheses

x^3+4x^2+5x^2+20x-4

We do not support expression: x^3

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