(x+3)(x+3)=(x+1)(x+2)

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Solution for (x+3)(x+3)=(x+1)(x+2) equation: 



(x+3)(x+3)=(x+1)(x+2)

We move all terms to the left:

(x+3)(x+3)-((x+1)(x+2))=0

We multiply parentheses ..

(+x^2+3x+3x+9)-((x+1)(x+2))=0



We calculate terms in parentheses: -((x+1)(x+2)), so:

(x+1)(x+2)

We multiply parentheses ..

(+x^2+2x+x+2)

We get rid of parentheses

x^2+2x+x+2

We add all the numbers together, and all the variables

x^2+3x+2

Back to the equation:

-(x^2+3x+2)



We get rid of parentheses

x^2-x^2+3x+3x-3x+9-2=0

We add all the numbers together, and all the variables

3x+7=0

We move all terms containing x to the left, all other terms to the right

3x=-7

x=-7/3

x=-2+1/3

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