(x+3)(x+3)=x-3(16+x-3)

Solution for (x+3)(x+3)=x-3(16+x-3) equation:

(x+3)(x+3)=x-3(16+x-3)

We move all terms to the left:

(x+3)(x+3)-(x-3(16+x-3))=0

We add all the numbers together, and all the variables

(x+3)(x+3)-(x-3(x+13))=0

We multiply parentheses ..

(+x^2+3x+3x+9)-(x-3(x+13))=0


We calculate terms in parentheses: -(x-3(x+13)), so:

x-3(x+13)

We multiply parentheses

x-3x-39

We add all the numbers together, and all the variables

-2x-39

Back to the equation:

-(-2x-39)


We get rid of parentheses

x^2+3x+3x+2x+9+39=0

We add all the numbers together, and all the variables

x^2+8x+48=0

a = 1; b = 8; c = +48;
Δ = b2-4ac
Δ = 82-4·1·48
Δ = -128
Delta is less than zero, so there is no solution for the equation