(x+3)(x+3)=x2+8x+15

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Solution for (x+3)(x+3)=x2+8x+15 equation: 



(x+3)(x+3)=x2+8x+15

We move all terms to the left:

(x+3)(x+3)-(x2+8x+15)=0

We add all the numbers together, and all the variables

-(+x^2+8x+15)+(x+3)(x+3)=0

We get rid of parentheses

-x^2-8x+(x+3)(x+3)-15=0

We multiply parentheses ..

-x^2+(+x^2+3x+3x+9)-8x-15=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+3x+3x+9)-8x-15=0

We get rid of parentheses

-1x^2+x^2+3x+3x-8x+9-15=0

We add all the numbers together, and all the variables

-2x-6=0

We move all terms containing x to the left, all other terms to the right

-2x=6

x=6/-2

x=-3

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