(x+3)(x+4)=(x+1)(x+4)

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Solution for (x+3)(x+4)=(x+1)(x+4) equation: 



(x+3)(x+4)=(x+1)(x+4)

We move all terms to the left:

(x+3)(x+4)-((x+1)(x+4))=0

We multiply parentheses ..

(+x^2+4x+3x+12)-((x+1)(x+4))=0



We calculate terms in parentheses: -((x+1)(x+4)), so:

(x+1)(x+4)

We multiply parentheses ..

(+x^2+4x+x+4)

We get rid of parentheses

x^2+4x+x+4

We add all the numbers together, and all the variables

x^2+5x+4

Back to the equation:

-(x^2+5x+4)



We get rid of parentheses

x^2-x^2+4x+3x-5x+12-4=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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