(x+3)(x+4)=(x+3)(x+4)

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Solution for (x+3)(x+4)=(x+3)(x+4) equation: 



(x+3)(x+4)=(x+3)(x+4)

We move all terms to the left:

(x+3)(x+4)-((x+3)(x+4))=0

We multiply parentheses ..

(+x^2+4x+3x+12)-((+x^2+4x+3x+12))=0



We calculate terms in parentheses: -((+x^2+4x+3x+12)), so:

(+x^2+4x+3x+12)

We get rid of parentheses

x^2+4x+3x+12

We add all the numbers together, and all the variables

x^2+7x+12

Back to the equation:

-(x^2+7x+12)



We get rid of parentheses

x^2-x^2+4x+3x-7x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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