(x+3)(x+4)=(x+3)(x+5)

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Solution for (x+3)(x+4)=(x+3)(x+5) equation:



(x+3)(x+4)=(x+3)(x+5)
We move all terms to the left:
(x+3)(x+4)-((x+3)(x+5))=0
We multiply parentheses ..
(+x^2+4x+3x+12)-((x+3)(x+5))=0
We calculate terms in parentheses: -((x+3)(x+5)), so:
(x+3)(x+5)
We multiply parentheses ..
(+x^2+5x+3x+15)
We get rid of parentheses
x^2+5x+3x+15
We add all the numbers together, and all the variables
x^2+8x+15
Back to the equation:
-(x^2+8x+15)
We get rid of parentheses
x^2-x^2+4x+3x-8x+12-15=0
We add all the numbers together, and all the variables
-1x-3=0
We move all terms containing x to the left, all other terms to the right
-x=3
x=3/-1
x=-3

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