(x+3)(x+4)=(x-2)(x+1)

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Solution for (x+3)(x+4)=(x-2)(x+1) equation: 



(x+3)(x+4)=(x-2)(x+1)

We move all terms to the left:

(x+3)(x+4)-((x-2)(x+1))=0

We multiply parentheses ..

(+x^2+4x+3x+12)-((x-2)(x+1))=0



We calculate terms in parentheses: -((x-2)(x+1)), so:

(x-2)(x+1)

We multiply parentheses ..

(+x^2+x-2x-2)

We get rid of parentheses

x^2+x-2x-2

We add all the numbers together, and all the variables

x^2-1x-2

Back to the equation:

-(x^2-1x-2)



We get rid of parentheses

x^2-x^2+4x+3x+1x+12+2=0

We add all the numbers together, and all the variables

8x+14=0

We move all terms containing x to the left, all other terms to the right

8x=-14

x=-14/8

x=-1+3/4

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