(x+3)(x+5)=(x+3)(x+5)

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Solution for (x+3)(x+5)=(x+3)(x+5) equation: 



(x+3)(x+5)=(x+3)(x+5)

We move all terms to the left:

(x+3)(x+5)-((x+3)(x+5))=0

We multiply parentheses ..

(+x^2+5x+3x+15)-((+x^2+5x+3x+15))=0



We calculate terms in parentheses: -((+x^2+5x+3x+15)), so:

(+x^2+5x+3x+15)

We get rid of parentheses

x^2+5x+3x+15

We add all the numbers together, and all the variables

x^2+8x+15

Back to the equation:

-(x^2+8x+15)



We get rid of parentheses

x^2-x^2+5x+3x-8x+15-15=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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