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(x+3)(x+5)=(x+3)(x+5)
We move all terms to the left:
(x+3)(x+5)-((x+3)(x+5))=0
We multiply parentheses ..
(+x^2+5x+3x+15)-((+x^2+5x+3x+15))=0
We calculate terms in parentheses: -((+x^2+5x+3x+15)), so:We get rid of parentheses
(+x^2+5x+3x+15)
We get rid of parentheses
x^2+5x+3x+15
We add all the numbers together, and all the variables
x^2+8x+15
Back to the equation:
-(x^2+8x+15)
x^2-x^2+5x+3x-8x+15-15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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