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(x+3)(x+5)=x2+6x+3
We move all terms to the left:
(x+3)(x+5)-(x2+6x+3)=0
We add all the numbers together, and all the variables
-(+x^2+6x+3)+(x+3)(x+5)=0
We get rid of parentheses
-x^2-6x+(x+3)(x+5)-3=0
We multiply parentheses ..
-x^2+(+x^2+5x+3x+15)-6x-3=0
We add all the numbers together, and all the variables
-1x^2+(+x^2+5x+3x+15)-6x-3=0
We get rid of parentheses
-1x^2+x^2+5x+3x-6x+15-3=0
We add all the numbers together, and all the variables
2x+12=0
We move all terms containing x to the left, all other terms to the right
2x=-12
x=-12/2
x=-6
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