(x+3)(x+7)=(x+9)(x+1)

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Solution for (x+3)(x+7)=(x+9)(x+1) equation: 



(x+3)(x+7)=(x+9)(x+1)

We move all terms to the left:

(x+3)(x+7)-((x+9)(x+1))=0

We multiply parentheses ..

(+x^2+7x+3x+21)-((x+9)(x+1))=0



We calculate terms in parentheses: -((x+9)(x+1)), so:

(x+9)(x+1)

We multiply parentheses ..

(+x^2+x+9x+9)

We get rid of parentheses

x^2+x+9x+9

We add all the numbers together, and all the variables

x^2+10x+9

Back to the equation:

-(x^2+10x+9)



We get rid of parentheses

x^2-x^2+7x+3x-10x+21-9=0

We add all the numbers together, and all the variables

12!=0

There is no solution for this equation

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