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(x+3)(x-12)=x2-x-12
We move all terms to the left:
(x+3)(x-12)-(x2-x-12)=0
We add all the numbers together, and all the variables
-(+x^2-1x-12)+(x+3)(x-12)=0
We get rid of parentheses
-x^2+1x+(x+3)(x-12)+12=0
We multiply parentheses ..
-x^2+(+x^2-12x+3x-36)+1x+12=0
We add all the numbers together, and all the variables
-1x^2+(+x^2-12x+3x-36)+x+12=0
We get rid of parentheses
-1x^2+x^2-12x+3x+x-36+12=0
We add all the numbers together, and all the variables
-8x-24=0
We move all terms containing x to the left, all other terms to the right
-8x=24
x=24/-8
x=-3
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