(x+3)(x-2)-(x+4)(x-1)=3

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Solution for (x+3)(x-2)-(x+4)(x-1)=3 equation: 



(x+3)(x-2)-(x+4)(x-1)=3

We move all terms to the left:

(x+3)(x-2)-(x+4)(x-1)-(3)=0

We multiply parentheses ..

(+x^2-2x+3x-6)-(x+4)(x-1)-3=0

We get rid of parentheses

x^2-2x+3x-(x+4)(x-1)-6-3=0

We multiply parentheses ..

x^2-(+x^2-1x+4x-4)-2x+3x-6-3=0

We add all the numbers together, and all the variables

x^2-(+x^2-1x+4x-4)+x-9=0

We get rid of parentheses

x^2-x^2+1x-4x+x+4-9=0

We add all the numbers together, and all the variables

-2x-5=0

We move all terms containing x to the left, all other terms to the right

-2x=5

x=5/-2

x=-2+1/2

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