(x+3)(x-2)-(x+4)(x-1)=3x

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Solution for (x+3)(x-2)-(x+4)(x-1)=3x equation: 



(x+3)(x-2)-(x+4)(x-1)=3x

We move all terms to the left:

(x+3)(x-2)-(x+4)(x-1)-(3x)=0

We add all the numbers together, and all the variables

-3x+(x+3)(x-2)-(x+4)(x-1)=0

We multiply parentheses ..

(+x^2-2x+3x-6)-3x-(x+4)(x-1)=0

We get rid of parentheses

x^2-2x+3x-3x-(x+4)(x-1)-6=0

We multiply parentheses ..

x^2-(+x^2-1x+4x-4)-2x+3x-3x-6=0

We add all the numbers together, and all the variables

x^2-(+x^2-1x+4x-4)-2x-6=0

We get rid of parentheses

x^2-x^2+1x-4x-2x+4-6=0

We add all the numbers together, and all the variables

-5x-2=0

We move all terms containing x to the left, all other terms to the right

-5x=2

x=2/-5

x=-2/5

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