(x+3)(x-2)=(x-4)(x-4)

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Solution for (x+3)(x-2)=(x-4)(x-4) equation: 



(x+3)(x-2)=(x-4)(x-4)

We move all terms to the left:

(x+3)(x-2)-((x-4)(x-4))=0

We multiply parentheses ..

(+x^2-2x+3x-6)-((x-4)(x-4))=0



We calculate terms in parentheses: -((x-4)(x-4)), so:

(x-4)(x-4)

We multiply parentheses ..

(+x^2-4x-4x+16)

We get rid of parentheses

x^2-4x-4x+16

We add all the numbers together, and all the variables

x^2-8x+16

Back to the equation:

-(x^2-8x+16)



We get rid of parentheses

x^2-x^2-2x+3x+8x-6-16=0

We add all the numbers together, and all the variables

9x-22=0

We move all terms containing x to the left, all other terms to the right

9x=22

x=22/9

x=2+4/9

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