(x+3)(x-2)=4

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Solution for (x+3)(x-2)=4 equation:



(x+3)(x-2)=4
We move all terms to the left:
(x+3)(x-2)-(4)=0
We multiply parentheses ..
(+x^2-2x+3x-6)-4=0
We get rid of parentheses
x^2-2x+3x-6-4=0
We add all the numbers together, and all the variables
x^2+x-10=0
a = 1; b = 1; c = -10;
Δ = b2-4ac
Δ = 12-4·1·(-10)
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{41}}{2*1}=\frac{-1-\sqrt{41}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{41}}{2*1}=\frac{-1+\sqrt{41}}{2} $

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