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(x+3)(x-2)=x2+x-6
We move all terms to the left:
(x+3)(x-2)-(x2+x-6)=0
We add all the numbers together, and all the variables
-(+x^2+x-6)+(x+3)(x-2)=0
We get rid of parentheses
-x^2-x+(x+3)(x-2)+6=0
We multiply parentheses ..
-x^2+(+x^2-2x+3x-6)-x+6=0
We add all the numbers together, and all the variables
-1x^2+(+x^2-2x+3x-6)-1x+6=0
We get rid of parentheses
-1x^2+x^2-2x+3x-1x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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