(x+3)(x-3)+2x(2x-1)=5x(x-2)

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Solution for (x+3)(x-3)+2x(2x-1)=5x(x-2) equation: 



(x+3)(x-3)+2x(2x-1)=5x(x-2)

We move all terms to the left:

(x+3)(x-3)+2x(2x-1)-(5x(x-2))=0

We use the square of the difference formula

x^2+2x(2x-1)-(5x(x-2))-9=0

We multiply parentheses

x^2+4x^2-2x-(5x(x-2))-9=0



We calculate terms in parentheses: -(5x(x-2)), so:

5x(x-2)

We multiply parentheses

5x^2-10x

Back to the equation:

-(5x^2-10x)



We add all the numbers together, and all the variables

5x^2-2x-(5x^2-10x)-9=0

We get rid of parentheses

5x^2-5x^2-2x+10x-9=0

We add all the numbers together, and all the variables

8x-9=0

We move all terms containing x to the left, all other terms to the right

8x=9

x=9/8

x=1+1/8

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