(x+3)(x-3)=(x+9)(x-8)

Solution for (x+3)(x-3)=(x+9)(x-8) equation:

(x+3)(x-3)=(x+9)(x-8)

We move all terms to the left:

(x+3)(x-3)-((x+9)(x-8))=0

We use the square of the difference formula

x^2-((x+9)(x-8))-9=0

We multiply parentheses ..

x^2-((+x^2-8x+9x-72))-9=0


We calculate terms in parentheses: -((+x^2-8x+9x-72)), so:

(+x^2-8x+9x-72)

We get rid of parentheses

x^2-8x+9x-72

We add all the numbers together, and all the variables

x^2+x-72

Back to the equation:

-(x^2+x-72)


We get rid of parentheses

x^2-x^2-x+72-9=0

We add all the numbers together, and all the variables

-1x+63=0

We move all terms containing x to the left, all other terms to the right

-x=-63

x=-63/-1

x=+63