(x+3)(x-3)=35

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Solution for (x+3)(x-3)=35 equation:



(x+3)(x-3)=35
We move all terms to the left:
(x+3)(x-3)-(35)=0
We use the square of the difference formula
x^2-9-35=0
We add all the numbers together, and all the variables
x^2-44=0
a = 1; b = 0; c = -44;
Δ = b2-4ac
Δ = 02-4·1·(-44)
Δ = 176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{176}=\sqrt{16*11}=\sqrt{16}*\sqrt{11}=4\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{11}}{2*1}=\frac{0-4\sqrt{11}}{2} =-\frac{4\sqrt{11}}{2} =-2\sqrt{11} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{11}}{2*1}=\frac{0+4\sqrt{11}}{2} =\frac{4\sqrt{11}}{2} =2\sqrt{11} $

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