(x+3)(x-3)=7x/4

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Solution for (x+3)(x-3)=7x/4 equation: 


x in (-oo:+oo)

(x+3)*(x-3) = (7*x)/4 // - (7*x)/4

(x+3)*(x-3)-((7*x)/4) = 0

(x+3)*(x-3)+(-7/4)*x = 0

(x+3)*(x-3)+(-7*x)/4 = 0

(4*(x+3)*(x-3))/4+(-7*x)/4 = 0

4*(x+3)*(x-3)-7*x = 0

4*x^2-7*x-36 = 0

4*x^2-7*x-36 = 0

4*x^2-7*x-36 = 0

DELTA = (-7)^2-(-36*4*4)

DELTA = 625

DELTA > 0

x = (625^(1/2)+7)/(2*4) or x = (7-625^(1/2))/(2*4)

x = 4 or x = -9/4

(x+9/4)*(x-4) = 0

((x+9/4)*(x-4))/4 = 0

((x+9/4)*(x-4))/4 = 0 // * 4

(x+9/4)*(x-4) = 0

( x+9/4 )

x+9/4 = 0 // - 9/4

x = -9/4

( x-4 )

x-4 = 0 // + 4

x = 4

x in { -9/4, 4 }

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