(x+3)(x-3)=x(1+x)

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Solution for (x+3)(x-3)=x(1+x) equation:



(x+3)(x-3)=x(1+x)
We move all terms to the left:
(x+3)(x-3)-(x(1+x))=0
We add all the numbers together, and all the variables
(x+3)(x-3)-(x(x+1))=0
We use the square of the difference formula
x^2-(x(x+1))-9=0
We calculate terms in parentheses: -(x(x+1)), so:
x(x+1)
We multiply parentheses
x^2+x
Back to the equation:
-(x^2+x)
We get rid of parentheses
x^2-x^2-x-9=0
We add all the numbers together, and all the variables
-1x-9=0
We move all terms containing x to the left, all other terms to the right
-x=9
x=9/-1
x=-9

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