(x+3)(x-3)=x(x-1)

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Solution for (x+3)(x-3)=x(x-1) equation:



(x+3)(x-3)=x(x-1)
We move all terms to the left:
(x+3)(x-3)-(x(x-1))=0
We use the square of the difference formula
x^2-(x(x-1))-9=0
We calculate terms in parentheses: -(x(x-1)), so:
x(x-1)
We multiply parentheses
x^2-1x
Back to the equation:
-(x^2-1x)
We get rid of parentheses
x^2-x^2+1x-9=0
We add all the numbers together, and all the variables
x-9=0
We move all terms containing x to the left, all other terms to the right
x=9

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