(x+3)(x-4)=4(2x-5)

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Solution for (x+3)(x-4)=4(2x-5) equation:


Simplifying
(x + 3)(x + -4) = 4(2x + -5)

Reorder the terms:
(3 + x)(x + -4) = 4(2x + -5)

Reorder the terms:
(3 + x)(-4 + x) = 4(2x + -5)

Multiply (3 + x) * (-4 + x)
(3(-4 + x) + x(-4 + x)) = 4(2x + -5)
((-4 * 3 + x * 3) + x(-4 + x)) = 4(2x + -5)
((-12 + 3x) + x(-4 + x)) = 4(2x + -5)
(-12 + 3x + (-4 * x + x * x)) = 4(2x + -5)
(-12 + 3x + (-4x + x2)) = 4(2x + -5)

Combine like terms: 3x + -4x = -1x
(-12 + -1x + x2) = 4(2x + -5)

Reorder the terms:
-12 + -1x + x2 = 4(-5 + 2x)
-12 + -1x + x2 = (-5 * 4 + 2x * 4)
-12 + -1x + x2 = (-20 + 8x)

Solving
-12 + -1x + x2 = -20 + 8x

Solving for variable 'x'.

Reorder the terms:
-12 + 20 + -1x + -8x + x2 = -20 + 8x + 20 + -8x

Combine like terms: -12 + 20 = 8
8 + -1x + -8x + x2 = -20 + 8x + 20 + -8x

Combine like terms: -1x + -8x = -9x
8 + -9x + x2 = -20 + 8x + 20 + -8x

Reorder the terms:
8 + -9x + x2 = -20 + 20 + 8x + -8x

Combine like terms: -20 + 20 = 0
8 + -9x + x2 = 0 + 8x + -8x
8 + -9x + x2 = 8x + -8x

Combine like terms: 8x + -8x = 0
8 + -9x + x2 = 0

Factor a trinomial.
(1 + -1x)(8 + -1x) = 0

Subproblem 1

Set the factor '(1 + -1x)' equal to zero and attempt to solve: Simplifying 1 + -1x = 0 Solving 1 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1x = 0 + -1 -1x = 0 + -1 Combine like terms: 0 + -1 = -1 -1x = -1 Divide each side by '-1'. x = 1 Simplifying x = 1

Subproblem 2

Set the factor '(8 + -1x)' equal to zero and attempt to solve: Simplifying 8 + -1x = 0 Solving 8 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1x = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1x = 0 + -8 -1x = 0 + -8 Combine like terms: 0 + -8 = -8 -1x = -8 Divide each side by '-1'. x = 8 Simplifying x = 8

Solution

x = {1, 8}

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