(x+3)(x-6)=x/2-39

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Solution for (x+3)(x-6)=x/2-39 equation:



(x+3)(x-6)=x/2-39
We move all terms to the left:
(x+3)(x-6)-(x/2-39)=0
We get rid of parentheses
(x+3)(x-6)-x/2+39=0
We multiply parentheses ..
(+x^2-6x+3x-18)-x/2+39=0
We multiply all the terms by the denominator
((+x^2-6x+3x-18))*2-x+39*2=0
We add all the numbers together, and all the variables
((+x^2-6x+3x-18))*2-1x+78=0
We move all terms containing x to the left, all other terms to the right
((+x^2-6x+3x-18))*2-1x=-78

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