(x+3)(x-7)/(x-5)(x+3)=1

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Solution for (x+3)(x-7)/(x-5)(x+3)=1 equation: 



(x+3)(x-7)/(x-5)(x+3)=1

We move all terms to the left:

(x+3)(x-7)/(x-5)(x+3)-(1)=0



Domain of the equation: (x-5)(x+3)!=0

We move all terms containing x to the left, all other terms to the right

x-5)(x!=-3

x∈R



We multiply parentheses ..

(+x^2-7x+3x-21)/(x-5)(x+3)-1=0

We multiply all the terms by the denominator


(+x^2-7x+3x-21)-1*(x-5)(x+3)=0

We get rid of parentheses

x^2-7x+3x-1*(x-5)(x+3)-21=0

We multiply parentheses ..

x^2-1*(+x^2+3x-5x-15)-7x+3x-21=0

We add all the numbers together, and all the variables

x^2-1*(+x^2+3x-5x-15)-4x-21=0

We move all terms containing x to the left, all other terms to the right

x^2-1*(+x^2+3x-5x-15)-4x=21

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