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(x+3)(x-8)=-30
We move all terms to the left:
(x+3)(x-8)-(-30)=0
We add all the numbers together, and all the variables
(x+3)(x-8)+30=0
We multiply parentheses ..
(+x^2-8x+3x-24)+30=0
We get rid of parentheses
x^2-8x+3x-24+30=0
We add all the numbers together, and all the variables
x^2-5x+6=0
a = 1; b = -5; c = +6;
Δ = b2-4ac
Δ = -52-4·1·6
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-1}{2*1}=\frac{4}{2} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+1}{2*1}=\frac{6}{2} =3 $
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