(x+3)*(4-x)=(x-4)*(-x+7)

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Solution for (x+3)*(4-x)=(x-4)*(-x+7) equation: 



(x+3)(4-x)=(x-4)(-x+7)

We move all terms to the left:

(x+3)(4-x)-((x-4)(-x+7))=0

We add all the numbers together, and all the variables

(x+3)(-1x+4)-((x-4)(-1x+7))=0

We multiply parentheses ..

(-1x^2+4x-3x+12)-((x-4)(-1x+7))=0



We calculate terms in parentheses: -((x-4)(-1x+7)), so:

(x-4)(-1x+7)

We multiply parentheses ..

(-1x^2+7x+4x-28)

We get rid of parentheses

-1x^2+7x+4x-28

We add all the numbers together, and all the variables

-1x^2+11x-28

Back to the equation:

-(-1x^2+11x-28)



We get rid of parentheses

-1x^2+1x^2+4x-3x-11x+12+28=0

We add all the numbers together, and all the variables

-10x+40=0

We move all terms containing x to the left, all other terms to the right

-10x=-40

x=-40/-10

x=+4

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