(x+3)*(x+3)=6x+45

Solution for (x+3)*(x+3)=6x+45 equation:

(x+3)(x+3)=6x+45

We move all terms to the left:

(x+3)(x+3)-(6x+45)=0

We get rid of parentheses

(x+3)(x+3)-6x-45=0

We multiply parentheses ..

(+x^2+3x+3x+9)-6x-45=0

We get rid of parentheses

x^2+3x+3x-6x+9-45=0

We add all the numbers together, and all the variables

x^2-36=0

a = 1; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·1·(-36)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*1}=\frac{-12}{2}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*1}=\frac{12}{2}
=6
$